3=-16t^2+30t+4

Solution for 3=-16t^2+30t+4 equation:

3=-16t^2+30t+4

We move all terms to the left:

3-(-16t^2+30t+4)=0

We get rid of parentheses

16t^2-30t-4+3=0

We add all the numbers together, and all the variables

16t^2-30t-1=0

a = 16; b = -30; c = -1;
Δ = b2-4ac
Δ = -302-4·16·(-1)
Δ = 964
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{964}=\sqrt{4*241}=\sqrt{4}*\sqrt{241}=2\sqrt{241}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-30)-2\sqrt{241}}{2*16}=\frac{30-2\sqrt{241}}{32}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-30)+2\sqrt{241}}{2*16}=\frac{30+2\sqrt{241}}{32}
$